2x^2+8y=x^2-8y

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Solution for 2x^2+8y=x^2-8y equation:


Simplifying
2x2 + 8y = x2 + -8y

Solving
2x2 + 8y = x2 + -8y

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1x2' to each side of the equation.
2x2 + -1x2 + 8y = x2 + -1x2 + -8y

Combine like terms: 2x2 + -1x2 = 1x2
1x2 + 8y = x2 + -1x2 + -8y

Combine like terms: x2 + -1x2 = 0
1x2 + 8y = 0 + -8y
1x2 + 8y = -8y

Add '-8y' to each side of the equation.
1x2 + 8y + -8y = -8y + -8y

Combine like terms: 8y + -8y = 0
1x2 + 0 = -8y + -8y
1x2 = -8y + -8y

Combine like terms: -8y + -8y = -16y
1x2 = -16y

Divide each side by '1'.
x2 = -16y

Simplifying
x2 = -16y

Combine like terms: -16y + 16y = 0
x2 + 16y = 0

The solution to this equation could not be determined.

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